输入代码:
/* *Copyright (c)2015,烟台大学计算机与控制工程学院 *All rights reserved. *文件名称:sum123.cpp *作 者:林海云 *完成日期:2015年6月12日 *版 本 号:v2.0 * *问题描述:在圆类上重载关系运算符(6种),使之能够按圆的面积比较两个圆的大小。自编main函数完成测试 *程序输入:无 *程序输出:按要求比较两圆面积的大小 */ #include <iostream> #include<Cmath> using namespace std; class Point { public: Point(double a=0,double b=0):x(a),y(b) {} protected: double x,y; }; class Circle:public Point //circle是Point类的公用派生类 { public: Circle(double a=0,double b=0,double r=0): Point(a,b),radius(r) { } double area ( ) const; //计算圆面积 friend ostream &operator<<(ostream &,const Circle &); //重载关系运算符运算符,使之能够按圆的面积比较两个圆的大小; bool operator>(const Circle &); bool operator<(const Circle &); bool operator>=(const Circle &); bool operator<=(const Circle &); bool operator==(const Circle &); bool operator!=(const Circle &); protected: double radius; }; //计算圆面积 double Circle::area( ) const { return 3.14159*radius*radius; } //重载运算符“<<”,使之按规定的形式输出圆的信息 ostream &operator<<(ostream &output,const Circle &c) { output<<"Center=["<<c.x<<", "<<c.y<<"], r="<<c.radius; return output; } //重载关系运算符(种)运算符,使之能够按圆的面积比较两个圆的大小; bool Circle::operator>(const Circle &c) { return (this->radius - c.radius) > 1e-7; } bool Circle::operator<(const Circle &c) { return (c.radius - this->radius) > 1e-7; } bool Circle::operator>=(const Circle &c) { return !(*this < c); } bool Circle::operator<=(const Circle &c) { return !(*this > c); } bool Circle::operator==(const Circle &c) { return abs(this->radius - c.radius) < 1e-7; } bool Circle::operator!=(const Circle &c) { return abs(this->radius - c.radius) > 1e-7; } int main( ) { Circle c1(3,2,4),c2(4,5,5); cout<<"圆c1( "<<c1<<" )的面积是 "<<c1.area()<<endl; cout<<"圆c2( "<<c2<<" )的面积是 "<<c2.area()<<endl; cout<<"圆c1 "; if(c1>c2) cout<<"圆c1大于圆c2."<<endl; if(c1<c2) cout<<"圆c1小于圆c2."<<endl; if(c1>=c2) cout<<"圆c1大于等于圆c2."<<endl; if(c1<=c2) cout<<"圆c1小于等于圆c2."<<endl; if(c1==c2) cout<<"圆c1等于圆c2."<<endl; if(c1!=c2) cout<<"圆c1不等于圆c2."<<endl; return 0; }
原文地址:http://blog.csdn.net/linhaiyun_ytdx/article/details/46475495