leetcode 1 twoSum

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</pre><pre name="code" class="cpp">

<p style="box-sizing: border-box; margin-top: 0px; margin-bottom: 10px; color: rgb(51, 51, 51); font-family: 'Helvetica Neue', Helvetica, Arial, sans-serif; font-size: 14px; line-height: 30px;">Given an array of integers, find two numbers such that they add up to a specific target number.</p><p style="box-sizing: border-box; margin-top: 0px; margin-bottom: 10px; color: rgb(51, 51, 51); font-family: 'Helvetica Neue', Helvetica, Arial, sans-serif; font-size: 14px; line-height: 30px;">The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note that your returned answers (both index1 and index2) are not zero-based.</p><p style="box-sizing: border-box; margin-top: 0px; margin-bottom: 10px; color: rgb(51, 51, 51); font-family: 'Helvetica Neue', Helvetica, Arial, sans-serif; font-size: 14px; line-height: 30px;">You may assume that each input would have exactly one solution.</p><p style="box-sizing: border-box; margin-top: 0px; margin-bottom: 10px; color: rgb(51, 51, 51); font-size: 14px; line-height: 30px; font-family: monospace;"><span style="box-sizing: border-box; font-weight: 700;">Input:</span> numbers={2, 7, 11, 15}, target=9<br style="box-sizing: border-box;" /><span style="box-sizing: border-box; font-weight: 700;">Output:</span> index1=1, index2=2</p>

#include <iostream>
#include <algorithm>
#include <map>
#include <vector>
#include <utility>
using namespace std;
class Solution
{
  public:
  vector<int> twoSum ( vector<int> &nums, int target )
  {
    vector<int> pg; //存放返回值
    map<int, int> Map;
    vector<int>::size_type i=0;
    for( ; i<nums.size() ; i++ )
    {
       if ( ! Map.count(nums[i]) )
       {
            Map.insert( make_pair( nums[i],  i ) ) ; //插入,  key是值, value 是下标
       }
     
       int tar = target - nums[i];
     
       if( Map.count (tar) )
       {
         int n= Map[tar]; 
         if ( n < i )
         {
          pg.push_back(n+1);
          pg.push_back(i+1);
         }
       }
    }
    
   return pg;
}

};

leetcode 1 twoSum

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原文地址：http://blog.csdn.net/nizhannizhan/article/details/46482335