码迷,mamicode.com
首页 > 其他好文 > 详细

[写代码]处理一组lrc歌词文件

时间:2015-06-14 16:24:35      阅读:102      评论:0      收藏:0      [点我收藏+]

标签:

看到博客http://wwj718.github.io/regex-demo2.html,又想用C++写文本处理了。

将如下文件:

[00:00.12]section 2.
[00:02.68]you will part of a radio programme about the opening of a new local sports shop.
[00:09.32]first you have some time to look at questions 11 to 16.
[00:39.64]now listen carefully and answer questions 11 to 16.
[00:48.24]now we go to Jane who is going to tell us about whats happening in town this weekend.
[00:52.24]right,thanks Andrew,
[00:53.92]and now on to whats new,
[00:56.48]and do we really need yet another sports shop in Bradcaster?
[01:01.24]well,most of you probably know Sports World-
[01:04.44]the branch of a Danish sports goods company that opened a few years ago-
[01:09.04]its attracted a lot of custom,
[01:11.36]and so the company has now decided to open another branch in the area.
[01:16.60]its going to be in the shopping centre to the west of Bradcaster,
[01:20.44]so that will be good news for all of you whove found the original shop in the north of the town hard to get to.
[01:27.12]i was invited to a special preview
[01:29.60]and i can promise you,this is the ultimate in sports retailing.
[211:29.60]dnasdasdjasiodjaoid

转换成:

   0.0     0.12  section 2.
  0.12     2.68  you will part of a radio programme about the opening of a new local sports shop.
  2.68     9.32  first you have some time to look at questions 11 to 16.
  9.32    39.64  now listen carefully and answer questions 11 to 16.
 39.64    48.24  now we go to Jane who is going to tell us about whats happening in town this weekend.
 48.24    52.24  right,thanks Andrew,
 52.24    53.92  and now on to whats new,
 53.92    56.48  and do we really need yet another sports shop in Bradcaster?
 56.48    61.24  well,most of you probably know Sports World-
 61.24    64.44  the branch of a Danish sports goods company that opened a few years ago-
 64.44    69.04  its attracted a lot of custom,
 69.04    71.36  and so the company has now decided to open another branch in the area.
 71.36    76.60  its going to be in the shopping centre to the west of Bradcaster,
 76.60    80.44  so that will be good news for all of you whove found the original shop in the north of the town hard to get to.
 80.44    87.12  i was invited to a special preview
 87.12    89.60  and i can promise you,this is the ultimate in sports retailing.
 89.60 12689.60  dnasdasdjasiodjaoid

在C++用正则的库进行匹配要扫好几遍,所以放弃使用正则了。

 

提供解决方案的代码如下:

  1 #include <iostream>
  2 #include <deque>
  3 #include <iomanip>
  4 #include <string>
  5 #include <cstring>
  6 #include <sstream>
  7 #include <fstream>
  8 #include <vector>
  9 
 10 using namespace std;
 11 
 12 typedef struct LINE {
 13     string time;
 14     string sentence;
 15 }LINE;
 16 
 17 typedef struct CLINE {
 18     string begin;
 19     string end;
 20     string sentence;
 21 }CLINE;
 22 
 23 string htom(string time) {
 24     string temp[3];    //h:m:s
 25     deque<int> sign;
 26     for (auto i = 0; i != time.length(); i++) {
 27         if (time[i] == . || time[i] == :) {
 28             sign.push_back(i);    //example: 01:27.12
 29         }
 30     }
 31     sign.push_back(time.size());    //end.
 32     int i = 0, t = 0, num[3];
 33     while (!sign.empty()) {
 34         for (; i != sign.front(); i++) {
 35             temp[t] += time[i];
 36         }
 37         t = t + 1;
 38         i = sign.front() + 1;
 39         sign.pop_front();
 40     }
 41     t = 0;    //set 0
 42     for (auto i = 0; i < 3; i++) {
 43         num[t++] = atoi(temp[i].data());    //convert
 44     }
 45     num[1] = num[0] * 60 + num[1];    //minute
 46     stringstream stoi;
 47     string last;
 48     if (num[2] > 10) {
 49         stoi << num[1] << "." << num[2];
 50     }
 51     else {
 52         stoi << num[1] << ".0" << num[2];
 53     }
 54     stoi >> last;
 55     return last;
 56 }
 57 
 58 void input(vector<LINE> &lrc) {
 59     ifstream fileRead("lrc.txt");
 60     while (!fileRead.eof()) {
 61         char stmp[1024];
 62         LINE ltmp;
 63         fileRead.getline(stmp, sizeof(stmp));
 64         int LEN = strlen(stmp);
 65         bool sflag = false;
 66 
 67         for (auto i = 1; i < LEN; i++) {
 68             if (stmp[i] == ]) {
 69                 sflag = true;
 70             }
 71             if (!sflag) {
 72                 ltmp.time += stmp[i];
 73                 continue;
 74             }
 75             if (stmp[i] != ]) {
 76                 ltmp.sentence += stmp[i];
 77             }
 78         }
 79         lrc.push_back(ltmp);
 80     }
 81     fileRead.close();
 82 }
 83 
 84 void convert(vector<LINE> &lrc, vector<CLINE> &cvt) {
 85     int LEN = lrc.size() - 1;
 86     for (auto i = 0; i != LEN; i++) {
 87         CLINE temp;
 88         if (i == 0) {
 89             temp.begin = "0.0";
 90         }
 91         else {
 92             temp.begin = htom(lrc[i - 1].time);
 93         }
 94         temp.end = htom(lrc[i].time);
 95         temp.sentence = lrc[i].sentence;
 96         cvt.push_back(temp);
 97     }
 98 }
 99 
100 void output(vector<CLINE> &cvt) {
101     ofstream fileWrite("cvtlrc.txt");
102     for (auto clrc : cvt) {
103         fileWrite << setw(6) << clrc.begin.data() << " "
104                   << setw(8) << clrc.end.data()
105                   << "  " << clrc.sentence.data() << endl;
106     }
107     fileWrite.close();
108 }
109 
110 int main() {
111     vector<LINE> lrc;
112     vector<CLINE> cvt;
113     input(lrc);
114     convert(lrc, cvt);
115     //for (auto clrc : cvt) {
116     //    cout << setw(6) << clrc.begin.data() << " "
117     //        << setw(8) << clrc.end.data()
118     //        << "  " << clrc.sentence.data() << endl;
119     //}
120     output(cvt);
121     return EXIT_SUCCESS;
122 }

 

[写代码]处理一组lrc歌词文件

标签:

原文地址:http://www.cnblogs.com/vincentX/p/4575135.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!