模拟货比交易 输入数据n 货币种类 m 交易种类 s 初始货币类型 v 初始持币数
m行分别为 A B(该种交易的两种货币A、B) RAB, CAB, RBA ,CBA A->B和B->A的交易汇率和手续费 交易后金额为(s-c)*r
最短路模板题 遍历看是否有正环(即可无限增加资本)
写了两种做法 SPFA比BellMan耗时长 可啪
SPFA
#include <cstdio>
#include <vector>
#include <queue>
#include <cstring>
#define esp 1e-8
using namespace std;
typedef struct Edge
{
int v;
double r,c;
}Edge;
Edge eg;
double dis[111];
int in[111];
bool vis[111];
vector <Edge> vct[111];
int n,m,s;
int dcmp(double x)
{
return x < -esp? -1: x > esp;
}
bool SPFA(double st)
{
memset(dis,0,sizeof(dis));
memset(in,0,sizeof(in));
dis[s] = st;
queue <int> q;
q.push(s);
int i,x,u,v;
double c,r;
while(!q.empty())
{
u = q.front();
q.pop();
vis[u] = 0;
for(i = 0; i < vct[u].size(); ++i)
{
v = vct[u][i].v;
c = vct[u][i].c;
r = vct[u][i].r;
if(dcmp(dis[v] - (dis[u]-c)*r) < 0)
{
dis[v] = (dis[u]-c)*r;
if(!vis[v])
{
in[v]++;
if(in[v] > n) return true;
q.push(v);
vis[v] = 1;
}
}
}
}
return false;
}
int main()
{
int i,u,v;
double sum;
scanf("%d %d %d %lf",&n,&m,&s,&sum);
for(i = 0; i < m; ++i)
{
scanf("%d %d %lf %lf",&u,&v,&eg.r,&eg.c);
eg.v = v;
vct[u].push_back(eg);
scanf("%lf %lf",&eg.r,&eg.c);
eg.v = u;
vct[v].push_back(eg);
}
if(SPFA(sum)) printf("YES\n");
else printf("NO\n");
return 0;
}
BellMan-Ford
#include <cstdio>
#include <vector>
#include <cstring>
#define esp 1e-8
using namespace std;
typedef struct Edge
{
int u,v;
double r,c;
}Edge;
Edge eg;
double dis[111];
vector <Edge> vct;
int n,m,s;
int dcmp(double x)
{
return x < -esp? -1: x > esp;
}
bool BellMan_Ford(double st)
{
memset(dis,0,sizeof(dis));
dis[s] = st;
int i,j,k,u,v,f;
double r,c;
for(i = 1; i < n; ++i)
{
f = 0;
for(j = 0; j < vct.size(); ++j)
{
u = vct[j].u;
v = vct[j].v;
r = vct[j].r;
c = vct[j].c;
if(dcmp(dis[v] - (dis[u]-c)*r) < 0)
{
dis[v] = (dis[u]-c)*r;
f = 1;
}
}
if(!f) return false;
}
for(j = 0; j < vct.size(); ++j)
{
u = vct[j].u;
v = vct[j].v;
r = vct[j].r;
c = vct[j].c;
if(dcmp(dis[v] - (dis[u]-c)*r) < 0)
{
return true;
}
}
return false;
}
int main()
{
int i,u,v;
double sum;
scanf("%d %d %d %lf",&n,&m,&s,&sum);
for(i = 0; i < m; ++i)
{
scanf("%d %d %lf %lf",&u,&v,&eg.r,&eg.c);
eg.v = v;
eg.u = u;
vct.push_back(eg);
scanf("%lf %lf",&eg.r,&eg.c);
eg.v = u;
eg.u = v;
vct.push_back(eg);
}
if(BellMan_Ford(sum)) printf("YES\n");
else printf("NO\n");
return 0;
}
原文地址:http://blog.csdn.net/challengerrumble/article/details/46506599