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Time limit: 1.0 second
Memory limit: 64 MB
Definition 1. n!!…! =
n(n?k)(n?2k)…(n mod k), if
k doesn’t divide n; n!!…! = n(n?k)(n?2k)…k, if
k divides n (There are k marks ! in the both cases).
Definition 2.X mod
Y — a remainder after division of X by Y.
For example, 10 mod 3 = 1; 3! = 3·2·1; 10!!! = 10·7·4·1.
Given numbers n and k we have calculated a value of the expression in the first definition. Can you do it as well?
Input
contains the only line: one integer n, 1 ≤
n ≤ 10, then exactly one space, then k exclamation marks, 1 ≤
k ≤ 20.
Output
contains one number — n!!…! (there are
k marks ! here).
Sample
Problem Author: Oleg Katz
Problem Source: The 3rd high school children programming contest, USU, Yekaterinburg, Russia, March 4, 2001
解析:直接按题目中的定义计算即可。
AC代码:
#include <bits/stdc++.h>
using namespace std;
int main(){
int n;
string s;
while(~scanf("%d", &n)){
cin>>s;
int k = s.size();
int ans = 1;
if(n % k){
int t = n / k;
for(int i=0; i<=t; i++){
ans *= (n - i * k);
}
}
else{
int t = n / k - 1;
for(int i=0; i<=t; i++){
ans *= (n - i * k);
}
}
printf("%d\n", ans);
}
return 0;
}
URAL 1083. Factorials!!! (阅读理解)
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原文地址:http://blog.csdn.net/u013446688/article/details/46509903