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URAL 1083. Factorials!!! (阅读理解)

时间:2015-06-15 23:55:48      阅读:154      评论:0      收藏:0      [点我收藏+]

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1083. Factorials!!!

Time limit: 1.0 second
Memory limit: 64 MB
Definition 1. n!!…! = n(n?k)(n?2k)…(n mod k), if k doesn’t divide n; n!!…! = n(n?k)(n?2k)…k, if k divides n (There are k marks ! in the both cases).
Definition 2.X mod Y — a remainder after division of X by Y.
For example, 10 mod 3 = 1; 3! = 3·2·1; 10!!! = 10·7·4·1.
Given numbers n and k we have calculated a value of the expression in the first definition. Can you do it as well?

Input

contains the only line: one integer n, 1 ≤ n ≤ 10, then exactly one space, then k exclamation marks, 1 ≤ k ≤ 20.

Output

contains one number — n!!…! (there are k marks ! here).

Sample

input output
9 !!
945
Problem Author: Oleg Katz
Problem Source: The 3rd high school children programming contest, USU, Yekaterinburg, Russia, March 4, 2001





解析:直接按题目中的定义计算即可。





AC代码:

#include <bits/stdc++.h>
using namespace std;

int main(){
    int n;
    string s;
    while(~scanf("%d", &n)){
        cin>>s;
        int k = s.size();
        int ans = 1;
        if(n % k){
            int t = n / k;
            for(int i=0; i<=t; i++){
                ans *= (n - i * k);
            }
        }
        else{
            int t = n / k - 1;
            for(int i=0; i<=t; i++){
                ans *= (n - i * k);
            }
        }
        printf("%d\n", ans);
    }
    return 0;
}


URAL 1083. Factorials!!! (阅读理解)

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原文地址:http://blog.csdn.net/u013446688/article/details/46509903

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