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说明:使用链表实现两个数的和,数的高位存储在链表的头部,最后输出结果。注:使用了翻转链表的功能。#include<stdio.h>
#include<stdlib.h>
struct Node
{
int value;
Node *next;
};
Node *reverseList(Node *head)
{
Node *pCur=head;
Node *pPre=NULL;
Node *rHead=NULL;
while(pCur!=NULL)
{
Node *pNext=pCur->next;
if(pNext==NULL)
rHead=pCur;
pCur->next=pPre;
pPre=pCur;
pCur=pNext;
}
return rHead;
}
Node *listAdd(Node *headm,Node *headn)
{
if(headm==NULL&&headn)
return headn;
else if(headn==NULL&&headm)
return headm;
else if(headn==NULL&&headm==NULL)
return NULL;
Node *pm=reverseList(headm);
Node *pn=reverseList(headn);
Node *head=(Node*)malloc(sizeof(Node));
Node *p=head;
p->next=NULL;
int tmp=0;
while(pm&&pn)
{
Node *q=(Node*)malloc(sizeof(Node));
if((pm->value+pn->value+tmp)>=10)
{
q->value=pm->value+pn->value-10+tmp;
tmp=1;
}
else
{
q->value=pm->value+pn->value+tmp;
tmp=0;
}
p->next=q;
p=q;
p->next=NULL;
pm=pm->next;
pn=pn->next;
}
while(pm)
{
Node *q=(Node*)malloc(sizeof(Node));
int count=pm->value+tmp;
if(count>=10)
{
q->value=count-10;
tmp=1;
}
else
{
q->value=count;
tmp=0;
}
p->next=q;
p=q;
p->next=NULL;
pm=pm->next;
}
while(pn)
{
Node *q=(Node*)malloc(sizeof(Node));
int count=pn->value+tmp;
if(count>=10)
{
q->value=count-10;
tmp=1;
}
else
{
q->value=count;
tmp=0;
}
p->next=q;
p=q;
p->next=NULL;
pn=pn->next;
}<span style="white-space:pre"> if(tmp)
<span style="white-space:pre"> </span>{
<span style="white-space:pre"> </span>Node *q=(Node*)malloc(sizeof(Node));
<span style="white-space:pre"> </span>q->value=1;
<span style="white-space:pre"> </span>p->next=q;
<span style="white-space:pre"> </span>p=q;
<span style="white-space:pre"> </span>p->next=NULL;
<span style="white-space:pre"> </span>}</span>
return reverseList(head->next);
}
int main()
{
int m,n,i;
while(scanf("%d %d",&m,&n)!=EOF)
{
Node* headm=(Node*)malloc(sizeof(Node));
Node* headn=(Node*)malloc(sizeof(Node));
Node *p1=headm,*p2=headn;
p1->next=NULL,p2->next=NULL;
for(i=0;i<m;i++)
{
int num;
scanf("%d",&num);
Node *tmp=(Node*)malloc(sizeof(Node));
tmp->value=num;
p1->next=tmp;
p1=tmp;
p1->next=NULL;
}
for(i=0;i<n;i++)
{
int num;
scanf("%d",&num);
Node *tmp=(Node*)malloc(sizeof(Node));
tmp->value=num;
p2->next=tmp;
p2=tmp;
p2->next=NULL;
}
Node *p=listAdd(headm->next,headn->next);
//Node *p=reverseList(headm->next);
while(p)
{
printf("%d ",p->value);
p=p->next;
}
printf("\n");
}
return 0;
}标签:
原文地址:http://blog.csdn.net/zyh920521/article/details/46522477