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快速幂取模模板

时间:2015-06-16 22:35:49      阅读:167      评论:0      收藏:0      [点我收藏+]

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 1 #include <iostream>
 2 #include <cstdio>
 3 #include <cmath>
 4 #include <vector>
 5 #include <cstring>
 6 #include <string>
 7 #include <algorithm>
 8 #include <string>
 9 #include <set>
10 #include <functional>
11 #include <numeric>
12 #include <sstream>
13 #include <stack>
14 #include <map>
15 #include <queue>
16 #pragma comment(linker, "/STACK:102400000,102400000")
17 #define CL(arr, val)    memset(arr, val, sizeof(arr))
18 
19 #define ll long long
20 #define inf 0x7f7f7f7f
21 #define lc l,m,rt<<1
22 #define rc m + 1,r,rt<<1|1
23 #define pi acos(-1.0)
24 
25 #define L(x)    (x) << 1
26 #define R(x)    (x) << 1 | 1
27 #define MID(l, r)   (l + r) >> 1
28 #define Min(x, y)   (x) < (y) ? (x) : (y)
29 #define Max(x, y)   (x) < (y) ? (y) : (x)
30 #define lson l,m,rt<<1
31 #define rson m+1,r,rt<<1|1
32 #define E(x)        (1 << (x))
33 #define iabs(x)     (x) < 0 ? -(x) : (x)
34 #define OUT(x)  printf("%I64d\n", x)
35 #define lowbit(x)   (x)&(-x)
36 #define Read()  freopen("a.txt", "r", stdin)
37 #define Write() freopen("b.txt", "w", stdout);
38 #define maxn 100010
39 #define mod 1000000007
40 using namespace std;
41 
42 ll quick_mod(ll a,ll b,ll c)
43 {
44     ll ans=1;
45     while(b)
46     {
47         if(b&1)
48         {
49             ans=(ans*a)%c;
50             b--;
51         }
52         b/=2;
53         a=(a*a)%c;
54     }
55     return ans;
56 }
57 int main()
58 {
59    // freopen("a.txt","r",stdin);
60     ll a,b,c;
61     scanf("%lld%lld%lld",&a,&b,&c);
62     printf("%lld\n",quick_mod(a,b,c));
63     return 0;
64 }

 

快速幂取模模板

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原文地址:http://www.cnblogs.com/nowandforever/p/4581900.html

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