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A typical backtracking problem. For any backtracking problem, you need to be think about three ascepts:
Of course, remember to recover to the previous status once a partial solution is done. In the following code, line 18 (sol.pop_back()) is for this purpose.
The following should be self-explanatory :)
1 class Solution { 2 public: 3 vector<vector<int>> combine(int n, int k) { 4 vector<vector<int> > res; 5 vector<int> sol; 6 combination(1, n, k, sol, res); 7 return res; 8 } 9 private: 10 void combination(int start, int n, int k, vector<int>& sol, vector<vector<int> >& res) { 11 if (k == 0) { 12 res.push_back(sol); 13 return; 14 } 15 for (int i = start; i <= n; i++) { 16 sol.push_back(i); 17 combination(i + 1, n, k - 1, sol, res); 18 sol.pop_back(); 19 } 20 } 21 };
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原文地址:http://www.cnblogs.com/jcliBlogger/p/4582166.html