标签:简单数学题
转载请注明出处:http://blog.csdn.net/u012860063
题目链接:http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=4452
题意: 给出两个点组成一条直线,要你任意输出两个点,要求这两点组成的直线和给出的直线垂直(注意输出的点不能有负数);
代码如下:
#include <cstdio> int main() { int n, x1, x2, y1, y2; int cas = 0; while(~scanf("%d",&n)) { while(n--) { scanf("%d%d%d%d",&x1,&y1,&x2,&y2); printf("Case %d: ",++cas); if(x1 == x2) { printf("0 0 1 0\n"); continue; } if(y1 == y2) { printf("0 0 0 1\n"); continue; } if(x1-x2>0 && y1-y2>0) { printf("%d 0 0 %d\n",y1-y2,x1-x2); } else if(x1-x2>0 && y1-y2<0) { printf("0 0 %d %d\n",y2-y1,x1-x2); } else if(x1-x2<0 && y1-y2>0) { printf("0 0 %d %d\n",y1-y2,x2-x1); } else if(x1-x2<0 && y1-y2<0) { printf("%d 0 0 %d\n",y2-y1,x2-x1); } } } return 0; }
UVA 12714 Two Points Revisited(简单数学题),布布扣,bubuko.com
UVA 12714 Two Points Revisited(简单数学题)
标签:简单数学题
原文地址:http://blog.csdn.net/u012860063/article/details/36214101