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LeetCode: Reverse Words in a String [151]

时间:2014-07-02 08:34:34      阅读:170      评论:0      收藏:0      [点我收藏+]

标签:leetcode   算法   面试   

【题目】

Given an input string, reverse the string word by word.

For example,
Given s = "the sky is blue",
return "blue is sky the".

click to show clarification.

Clarification:

  • What constitutes a word?
    A sequence of non-space characters constitutes a word.
  • Could the input string contain leading or trailing spaces?
    Yes. However, your reversed string should not contain leading or trailing spaces.
  • How about multiple spaces between two words?
    Reduce them to a single space in the reversed string.

【题意】

    给定一个字符串,按单词反转


【思路】

    现切分字符串,然后反向拼接


【代码】

class Solution {
public:
	
    void reverseWords(string &s) {
        stack<string> words;
		int start = -1;	//记录单词开始的位置
		for(int i=0; i<s.length(); i++){
			if(s[i]==' '){
				if(i!=0 && s[i-1]!=' '){
					//一个单词结束
					words.push(s.substr(start, i-start));
					start = -1;
				}
			}
			else{
				if(i==0 || s[i-1]==' '){
					start = i;
				}
			}
		}
		if(start!=-1)words.push(s.substr(start, s.length()-start));
		
		//拼接成反向单词
		s = "";
		int count=0;
		while(!words.empty()){
			count++;
			if(count==1)s+=words.top();
			else s+=" "+words.top();
			words.pop();
		}
    }
};


LeetCode: Reverse Words in a String [151],布布扣,bubuko.com

LeetCode: Reverse Words in a String [151]

标签:leetcode   算法   面试   

原文地址:http://blog.csdn.net/harryhuang1990/article/details/36204923

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