码迷,mamicode.com
首页 > 其他好文 > 详细

Codeforces546B:Soldier and Badges

时间:2015-06-18 15:20:34      阅读:106      评论:0      收藏:0      [点我收藏+]

标签:codeforces

题意:
给出一些数字,要求每个数字都不一样需要增加几


思路:

先排序,然后一个个增加,最后求总和差



#include <iostream>
#include <stdio.h>
#include <string.h>
#include <string>
#include <stack>
#include <queue>
#include <map>
#include <set>
#include <vector>
#include <math.h>
#include <bitset>
#include <list>
#include <algorithm>
#include <climits>
using namespace std;

#define lson 2*i
#define rson 2*i+1
#define LS l,mid,lson
#define RS mid+1,r,rson
#define UP(i,x,y) for(i=x;i<=y;i++)
#define DOWN(i,x,y) for(i=x;i>=y;i--)
#define MEM(a,x) memset(a,x,sizeof(a))
#define W(a) while(a)
#define gcd(a,b) __gcd(a,b)
#define LL long long
#define N 5000005
#define INF 0x3f3f3f3f
#define EXP 1e-8
#define lowbit(x) (x&-x)
const int mod = 1e9+7;
#define LL __int64
int n,a[3005];
int main()
{
    int i,j,ans;
    while(~scanf("%d",&n))
    {
        ans = 0;
        int sum1 = 0,sum2 = 0;
        for(i = 1; i<=n; i++)
        {
            scanf("%d",&a[i]);
            sum1+=a[i];
        }
        sort(a+1,a+1+n);
        sum2 = a[1];
        for(i = 2; i<=n; i++)
        {
            if(a[i] == a[i-1])
                a[i]++;
            else if(a[i]<a[i-1])
                a[i] +=(a[i-1]-a[i])+1;
            sum2+=a[i];
        }
        printf("%d\n",sum2-sum1);
    }

    return 0;
}


Codeforces546B:Soldier and Badges

标签:codeforces

原文地址:http://blog.csdn.net/libin56842/article/details/46547915

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!