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leetcode 226: Invert Binary Tree

时间:2015-06-19 01:33:32      阅读:140      评论:0      收藏:0      [点我收藏+]

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Invert Binary Tree

Total Accepted: 11286 Total Submissions: 32033

Invert a binary tree.

     4
   /     2     7
 / \   / 1   3 6   9
to
     4
   /     7     2
 / \   / 9   6 3   1
Trivia:
This problem was inspired by this original tweet by Max Howell:
Google: 90% of our engineers use the software you wrote (Homebrew), but you can’t invert a binary tree on a whiteboard so fuck off.

[思路]

递归交换左右子树

[CODE]

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
public class Solution {
    public TreeNode invertTree(TreeNode root) {
        if(root==null) return null;
        
        TreeNode temp  = root.left;
        root.left = root.right;
        root.right = temp;
        
        invertTree(root.left);
        invertTree(root.right);
        
        return root;    
    }
    
}


leetcode 226: Invert Binary Tree

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原文地址:http://blog.csdn.net/xudli/article/details/46554861

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