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1 >> clear 2 node = [1 1;-1 1;-1 -1;1 -1]; % nodes squar 3 elem = [1 2 3 4]; % elements 4 belong=1:size(elem,1); bdEdge=[1 1 1 1]; 5 for k1=1:2 6 [node,elem,bdEdge,HB,belong] = refine(node,elem,bdEdge,[],belong); 7 end 8 elem 9 10 elem = 11 12 1 10 22 11 13 5 12 23 18 14 9 20 24 21 15 6 19 25 16 16 10 5 18 22 17 12 2 13 23 18 20 7 14 24 19 19 9 21 25 20 22 18 9 19 21 23 13 7 20 22 24 14 3 15 23 25 21 8 17 24 11 22 19 6 25 18 23 20 9 26 21 24 15 8 27 16 25 17 4
用refine函数2次加密后的单元标号阵elem,可以看出总体节点编号的分布情况
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原文地址:http://www.cnblogs.com/wangshixi12/p/4590433.html