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Description:
Given an array of integers, every element appears twice except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
Code:
1 int singleNumber(vector<int>& nums) { 2 int result = 0; 3 for (int i = 0; i < nums.size(); ++i) 4 { 5 result^=nums[i]; 6 } 7 return result; 8 }
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原文地址：http://www.cnblogs.com/happygirl-zjj/p/4592121.html
