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Leetcode 01 Two Sum
Given an array of integers, find two numbers such that they add up to a specific target number.
The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note that your returned answers (both index1 and index2) are not zero-based.
You may assume that each input would have exactly one solution.
Input: numbers={2, 7, 11, 15}, target=9
Output: index1=1, index2=2
第一种解法 排序
class Solution { private: class node { public: int no; int val; }; class cmp_class { public: bool operator ()(const node& a, const node& b) { return a.val < b.val; } }cmp; public: vector<int> twoSum(vector<int>& nums, int target) { vector<node> line; vector<int> result(2,0); for (vector<int>::const_iterator it=nums.begin();it!=nums.end();it++) { node *temp=new node; (*temp).no=it-nums.begin()+1;(*temp).val=(*it); line.push_back(*temp); delete temp; } sort(line.begin(),line.end(),cmp); vector<node>::const_iterator l=line.begin(); vector<node>::const_iterator r=line.end()-1; while (l<r) { int *p=new int; *p=(*l).val+(*r).val; if ((*p)==target) { result[0]=min((*l).no,(*r).no); result[1]=max((*l).no,(*r).no); break; } else if ((*p)<target) { l++; } else { r--; } delete p; } return result; } };
第二种解法 map
class Solution2 { public: vector<int> twoSum(vector<int>& nums, int target) { map<int, int> hmap; vector<int> result; for (vector<int>::const_iterator iter = nums.begin(); iter != nums.end(); iter++) { map<int, int>::const_iterator fit = hmap.find(target-*iter); if (fit == hmap.end()) { hmap.insert(pair<int, int>( *iter,iter-nums.begin()+1)); } else { result.push_back(fit->second); result.push_back(iter - nums.begin() + 1); break; } } return result; } };
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原文地址：http://www.cnblogs.com/chenwanqq-leetcode/p/4596345.html
