标签:
Description:
Given an array of integers, every element appears twice except for one. Find that single one.
找出只出现一次的数。
public class Solution { public int singleNumber(int[] nums) { Map<Integer, Integer> map = new HashMap<Integer, Integer>(); for(int i=0; i<nums.length; i++) { if(map.containsKey(nums[i])) { int times = map.get(nums[i]); map.put(nums[i], times+1); } else map.put(nums[i], 1); } Set<Integer> set = map.keySet(); for(int i : set) { if(map.get(i) == 1) { return i; } } return 0; } }
标签:
原文地址:http://www.cnblogs.com/wxisme/p/4598908.html