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Invert Binary Tree——LeetCode

时间:2015-06-25 11:59:45      阅读:121      评论:0      收藏:0      [点我收藏+]

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Invert a binary tree.

     4
   /     2     7
 / \   / 1   3 6   9

to

     4
   /     7     2
 / \   / 9   6 3   1

Trivia:
This problem was inspired by this original tweet by Max Howell:

Google: 90% of our engineers use the software you wrote (Homebrew), but you can’t invert a binary tree on a whiteboard so fuck off.

 

哈哈,这题是homebrew作者面Google的题目,反转二叉树。

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
public class Solution {
    public TreeNode invertTree(TreeNode root) {
        if(root==null){
            return null;
        }
        TreeNode tmp = root.left;
        root.left=root.right;
        root.right=tmp;
        invertTree(root.left);
        invertTree(root.right);
        return root;
    }
}

 

Invert Binary Tree——LeetCode

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原文地址:http://www.cnblogs.com/aboutblank/p/4599484.html

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