标签:c++
题目链接:
http://codevs.cn/problem/1099/
题解思路:
1.用string 类型来保存字符串 方便插入比较等操作
2.用STL set<string>来判断当前字符串是否出现过
注意字符串的下标
代码:
#include<iostream>
#include<cstdio>
#include<cstring>
#include<queue>
#include<vector>
#include<set>
using namespace std;
struct node
{
    string str;
    int step;
} head;
struct node2
{
    string a,b;
};
vector<node2>edge;             //存边
set<string>M;
void bfs(string start,string endd)
{
    queue<node>q;
    M.insert(start);
    q.push( {start,0});
    while(!q.empty())
    {
        head=q.front();
        q.pop();
        if(head.str==endd)
        {
            cout<<head.step<<endl;
            return;
        }
        int len=head.str.length();
        for(int i=0; i<edge.size(); i++)
        {
            for(int j=0; j<(int)len-(int)edge[i].a.length()+1; j++)    //如果a的length()比 b的length()要小  则a.length()-b.length()结果会出错
                if(edge[i].a==head.str.substr(j,edge[i].a.size()))
                {
                    string d;
                    d.append(head.str,0,j);
                    d.append(edge[i].b);
                    d.append(head.str,j+edge[i].a.size(),string::npos);       //从j+edge[i].a.size()到末尾 全部push_back
                    if(M.find(d)==M.end()){          //用set判重
                        M.insert(d);
                        q.push({d,head.step+1});
                    }
                }
        }
    }
    cout<<"NO ANSWER!"<<endl;
    return;
}
int main()
{
    string start,endd,a,b;
    cin>>start>>endd;
    while(cin>>a>>b)
        edge.push_back( {a,b});
    bfs(start,endd);
    return 0;
}
标签:c++
原文地址:http://blog.csdn.net/axuan_k/article/details/46641445