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[leetcode] Validate Binary Search Tree

时间:2014-07-03 19:36:49      阅读:196      评论:0      收藏:0      [点我收藏+]

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Given a binary tree, determine if it is a valid binary search tree (BST).

Assume a BST is defined as follows:

  • The left subtree of a node contains only nodes with keys less than the node‘s key.
  • The right subtree of a node contains only nodes with keys greater than the node‘s key.
  • Both the left and right subtrees must also be binary search trees.

https://oj.leetcode.com/problems/validate-binary-search-tree/

 

思路1:递归求解,每个节点有一对valid的范围参数。

思路2:中序遍历,看是否是递增序列。

 

bubuko.com,布布扣
public class Solution {

    public boolean isValidBST(TreeNode root) {
        return check(root, Integer.MIN_VALUE, Integer.MAX_VALUE);
    }

    private boolean check(TreeNode root, int min, int max) {
        if (root == null)
            return true;
        if (root.val >= max || root.val <= min)
            return false;
        return check(root.left, min, root.val) && check(root.right, root.val, max);

    }

    public static void main(String[] args) {
        TreeNode root = new TreeNode(10);
        root.left = new TreeNode(5);
        root.left.right = new TreeNode(9);
        root.right = new TreeNode(20);
        root.right.left = new TreeNode(11);

        System.out.println(new Solution().isValidBST(root));

    }

}
View Code

 

[leetcode] Validate Binary Search Tree,布布扣,bubuko.com

[leetcode] Validate Binary Search Tree

标签:des   style   blog   http   color   strong   

原文地址:http://www.cnblogs.com/jdflyfly/p/3821272.html

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