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1 class Solution { 2 public: 3 // param n : description of n 4 // return: description of return 5 long long trailingZeros(long long n) { 6 long long counts = 0; 7 for(long long i = 5; n / i; i *= 5) 8 counts += n / i; 9 return counts; 10 } 11 };
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原文地址：http://www.cnblogs.com/jcliBlogger/p/4605748.html
