括号配对问题

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描述：

　　　现在，有一行括号序列，请你检查这行括号是否配对。

输入:

第一行输入一个数N（0<N<=100）,表示有N组测试数据。后面的N行输入多组输入数据，每组输入数据都是一个字符串S(S的长度小于10000，且S不是空串），测试数据组数少于5组。数据保证S中只含有"[","]","(",")"四种字符

输出:

每组输入数据的输出占一行，如果该字符串中所含的括号是配对的，则输出Yes,如果不配对则输出No

样例输入：

3
[(])
(])
([[]()])

样例输出：

No
No
Yes

---

import java.util.Scanner;

public class No2 {

    private String checkout(String str) {
        try {
            StringBuffer asb = new StringBuffer(str);  // 模拟栈A
            StringBuffer bsb = new StringBuffer();   // 模拟栈B
            int length = asb.length();

            while (length > 0) {
                // 遇右括号，移A入B
                if (asb.charAt(length - 1) == ‘)‘
                        || asb.charAt(length - 1) == ‘]‘) {
                    bsb.append(asb.charAt(length - 1));
                    asb.deleteCharAt(length - 1);
                    length = asb.length();
                    continue;
                }
                // 遇左括号，若无法与B中栈顶元素合法匹配，则序列非法；若合法匹配，移A移B
                if (asb.charAt(length - 1) == ‘(‘) {
                    if (bsb.charAt(bsb.length() - 1) != ‘)‘) {
                        return "No";
                    } else {
                        asb.deleteCharAt(asb.length() - 1);
                        bsb.deleteCharAt(bsb.length() - 1);
                        length = asb.length();
                        continue;
                    }
                }
                if (asb.charAt(length - 1) == ‘[‘) {
                    if (bsb.charAt(bsb.length() - 1) != ‘]‘) {
                        return "No";
                    } else {
                        asb.deleteCharAt(asb.length() - 1);
                        bsb.deleteCharAt(bsb.length() - 1);
                        length = asb.length();
                        continue;
                    }
                }
            }

            if (bsb.length() == 0) {
                return "Yes";
            }
        } catch (RuntimeException e) {

        }
        return "No";
    }

    public static void main(String args[]) throws Exception {
        try {
            Scanner cin = new Scanner(System.in);
            int num = cin.nextInt();
            String[] result = new String[num];
            No2 no2 = new No2();

            for (int i = 0; i < num; i++) {
                String str = cin.next();
                result[i] = no2.checkout(str);
            }

            for (int i = 0; i < num; i++) {
                System.out.println(result[i]);
            }
        } catch (RuntimeException e) {

        }
    }
}

 

括号配对问题

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原文地址：http://www.cnblogs.com/lifelonglearner/p/4611466.html