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Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘
, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World"
,
return 5
.
实现题。
public class Solution {
public int lengthOfLastWord(String s) {
char[] c = s.toCharArray();
int count = 0;
for (int i = c.length - 1; i >= 0; i--) {
if (c[i] == ‘ ‘ && count > 0) {
break;
}
if (c[i] != ‘ ‘) {
count++;
}
}
return count;
}
}
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原文地址:http://www.cnblogs.com/shini/p/4612700.html