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【级数】 求和

时间:2014-05-03 22:29:12      阅读:296      评论:0      收藏:0      [点我收藏+]

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证明

bubuko.com,布布扣n=0bubuko.com,布布扣bubuko.com,布布扣(n!)bubuko.com,布布扣2bubuko.com,布布扣2bubuko.com,布布扣n+1bubuko.com,布布扣bubuko.com,布布扣(2n+1)!bubuko.com,布布扣bubuko.com,布布扣=πbubuko.com,布布扣
 

 

分析:这道题初看具有难度运用幂级数恐难解决,由分子分母的特性易想到 $\Gamma$函数然后利用$\Gamma$函数与$\beta$函数的关系即可。

 

Proof: 

 
bubuko.com,布布扣n=0bubuko.com,布布扣bubuko.com,布布扣(n!)bubuko.com,布布扣2bubuko.com,布布扣2bubuko.com,布布扣n+1bubuko.com,布布扣bubuko.com,布布扣(2n+1)!bubuko.com,布布扣bubuko.com,布布扣bubuko.com,布布扣bubuko.com,布布扣bubuko.com,布布扣bubuko.com,布布扣bubuko.com,布布扣bubuko.com,布布扣=bubuko.com,布布扣n=0bubuko.com,布布扣bubuko.com,布布扣bubuko.com,布布扣1bubuko.com,布布扣0bubuko.com,布布扣tbubuko.com,布布扣nbubuko.com,布布扣(1?t)bubuko.com,布布扣nbubuko.com,布布扣2bubuko.com,布布扣n+1bubuko.com,布布扣dtbubuko.com,布布扣=2bubuko.com,布布扣1bubuko.com,布布扣0bubuko.com,布布扣bubuko.com,布布扣0bubuko.com,布布扣bubuko.com,布布扣tbubuko.com,布布扣nbubuko.com,布布扣(1?t)bubuko.com,布布扣nbubuko.com,布布扣2bubuko.com,布布扣nbubuko.com,布布扣dtbubuko.com,布布扣=bubuko.com,布布扣1bubuko.com,布布扣0bubuko.com,布布扣1bubuko.com,布布扣(t?1bubuko.com,布布扣2bubuko.com,布布扣bubuko.com,布布扣)+1bubuko.com,布布扣4bubuko.com,布布扣bubuko.com,布布扣bubuko.com,布布扣bubuko.com,布布扣dtbubuko.com,布布扣=2 arctan2(t?1bubuko.com,布布扣2bubuko.com,布布扣bubuko.com,布布扣)|bubuko.com,布布扣1bubuko.com,布布扣0bubuko.com,布布扣bubuko.com,布布扣=πbubuko.com,布布扣bubuko.com,布布扣bubuko.com,布布扣
 

 

Remark:交换积分与极限的次序用到了 Levi 渐升定理。

【级数】 求和,布布扣,bubuko.com

【级数】 求和

标签:style   class   ext   color   width   int   

原文地址:http://www.cnblogs.com/zhangwenbiao/p/3705281.html

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