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class Solution:
# @param {integer[]} prices
# @return {integer}
def maxProfit(self, prices):
profit = 0;
for i in xrange(1, len(prices)):
if prices[i] > prices[i-1]:
profit += prices[i] - prices[i-1]
return profit
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Leetcode Best Time to Buy and Sell Stock II
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原文地址：http://blog.csdn.net/andrew9tech/article/details/46756331
