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(Figure 1)
Figure 1 shows a number triangle. Write a program that calculates the highest sum of numbers passed on a route that starts at the top and ends somewhere on the base. Each step can go either diagonally down to the left or diagonally down to the right.
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30
//从下往上推
#include<iostream> #include<stdio.h> using namespace std; int main() { int n,i,j; int a[100][100]; while(cin>>n) { for(i=0;i<n;i++) for(j=0;j<=i;j++) cin>>a[i][j]; for(i=n-2;i>=0;i--) { for(j=0;j<=i;j++) { a[i][j]+=a[i+1][j]>a[i+1][j+1]?a[i+1][j]:a[i+1][j+1]; } } cout<<a[0][0]<<endl; } return 0; }
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原文地址:http://blog.csdn.net/phytn/article/details/46762181