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leetCode(33):Rectangle Area

时间:2015-07-08 09:33:41      阅读:138      评论:0      收藏:0      [点我收藏+]

标签:leetcode

Find the total area covered by two rectilinear rectangles in a 2D plane.

Each rectangle is defined by its bottom left corner and top right corner as shown in the figure.

技术分享

Assume that the total area is never beyond the maximum possible value of int.


class Solution {
public:
    int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) {
        int area1=(C-A)*(D-B);
    	int area2=(G-E)*(H-F);
    	if(B>=H || F>=D || E>=C || G<=A)
    	{//如果不相交
    		return area1+area2;
    	}
    	else
    	{
    		int length,width;
    		width=min(C,G)-max(A,E);//宽
    		length=min(D,H)-max(B,F);//长
    		return area1+area2-length*width;//面积之和减去重合部分面积		
    	}
    }
};


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leetCode(33):Rectangle Area

标签:leetcode

原文地址:http://blog.csdn.net/walker19900515/article/details/46798639

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