//尖括号内还可以设置指针类型或自定义类型。
stack的push()与pop()方法
stack.push(elem); //往栈头添加元素
stack.pop(); //从栈头移除第一个元素
stack<int> stkInt;
stkInt.push(1);stkInt.push(3);stkInt.pop();
stkInt.push(5);stkInt.push(7);
stkInt.push(9);stkInt.pop();
stkInt.pop();
此时stkInt存放的元素是1,5
stack对象的拷贝构造与赋值
stack(const stack &stk); //拷贝构造函数
stack& operator=(const stack &stk); //重载等号操作符
stack<int> stkIntA;
stkIntA.push(1);
stkIntA.push(3);
stkIntA.push(5);
stkIntA.push(7);
stkIntA.push(9);
stack<int> stkIntB(stkIntA); //拷贝构造
stack<int> stkIntC;
stkIntC = stkIntA; //赋值
stack的数据存取
? <span style="white-space:pre"> </span>stack.top(); //返回最后一个压入栈元素
stack<int> stkIntA;
stkIntA.push(1);
stkIntA.push(3);
stkIntA.push(5);
stkIntA.push(7);
stkIntA.push(9);
int iTop = stkIntA.top(); //9
stkIntA.top() = 19; //19
stack的大小
? stack.empty(); //判断堆栈是否为空
? stack.size(); //返回堆栈的大小
stack<int> stkIntA;
stkIntA.push(1);
stkIntA.push(3);
stkIntA.push(5);
stkIntA.push(7);
stkIntA.push(9);
if (!stkIntA.empty())
{
int iSize = stkIntA.size(); //5
}
#include <iostream>
#include <cstdio>
#include <stack>
#include <algorithm>
using namespace std;
void stackInit()
{
stack<int> s;
// 入栈
for (int i = 0; i < 10; ++i) {
s.push(i + 1);
}
cout << "size of s: " << s.size() << endl;
while (!s.empty()) {
cout << s.top() << ' '; // 获取栈顶元素
s.pop(); // 弹出栈顶元素
}
cout << endl;
}
class Teacher
{
public:
int age;
char name[32];
public:
void printTeacher()
{
cout << "age: " << age << endl;
}
};
void stackClass()
{
Teacher t1, t2, t3;
t1.age = 21;
t2.age = 22;
t3.age = 23;
stack<Teacher> s;
s.push(t1);
s.push(t2);
s.push(t3);
while (!s.empty()) {
Teacher tmp = s.top();
s.pop();
tmp.printTeacher();
}
/*
age: 23
age: 22
age: 21
*/
cout << endl;
}
void stackClassP()
{
Teacher t1, t2, t3;
t1.age = 21;
t2.age = 22;
t3.age = 23;
stack<Teacher *> s;
s.push(&t1);
s.push(&t2);
s.push(&t3);
while (!s.empty()) {
Teacher *tmp = s.top();
s.pop();
tmp->printTeacher();
}
/*
age: 23
age: 22
age: 21
*/
}
int main()
{
stackInit();
stackClass();
stackClassP();
return 0;
}
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原文地址:http://blog.csdn.net/zyq522376829/article/details/46802545