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Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World",
return 5.
public class Solution {
public int lengthOfLastWord(String s) {
int length = 0;
int i;
char[] charArray = s.toCharArray();
i = s.length() - 1;
while (i > -1 && charArray[i] == ‘ ‘) {
i--;
}
if (i < 0) {
length = 0;
} else {
for (int index = i; index > -1; index--) {
System.out.println(charArray[index]);
if (charArray[index] != ‘ ‘) {
length++;
} else {
break;
}
}
}
return length;
}
}
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原文地址：http://www.cnblogs.com/six-moon/p/4633788.html
