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Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.
For example,"A man, a plan, a canal: Panama"
is a palindrome."race a car"
is not a palindrome.
Note:
Have you consider that the string might be empty? This is a good question to ask during an interview.
For the purpose of this problem, we define empty string as valid palindrome.
class Solution { public: bool isPalindrome(string s) { int left= 0 , right = s.length()-1; while(left <= right){ while(left<=right && !isalnum(s[left])) left++; while(left<=right && !isalnum(s[right])) right--; if(left > right) break; if(isalpha(s[left]) && isalpha(s[right]) && tolower(s[left]) == tolower(s[right])){ left++; right--; } else if(isdigit(s[left])&& isdigit(s[right]) && s[left] == s[right]){ left++; right--; } else break; } if(left <= right) return false; else return true; } };
Leetcode Valid Palindrome,布布扣,bubuko.com
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原文地址:http://www.cnblogs.com/xiongqiangcs/p/3825253.html