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#include<cstdio>
#include<cstring>
#include<cmath>
#include<iostream>
#include<algorithm>
using namespace std;
int a[100+10];
int dp[120][120];
int sum[120];
int vis[120][120];
int dfs(int f,int t)
{
int i,j,k;
if(vis[f][t]==1) return dp[f][t];
vis[f][t]=1;
int minn=0;
for(i=f;i<t;i++)
{
minn=min(minn,dfs(f,i));
}
for(i=f+1;i<=t;i++)
{
minn=min(minn,dfs(i,t));
}
dp[f][t]=sum[t]-sum[f-1]-minn;
return dp[f][t];
}
int main()
{
int n;
int i,j,k;
while(scanf("%d",&n),n)
{
sum[0]=0;
memset(vis,0,sizeof(vis));
for(i=1;i<=n;i++)
{
scanf("%d",&a[i]);
sum[i]=sum[i-1]+a[i];
}
dfs(1,n);
printf("%d\n",dp[1][n]-(sum[n]-dp[1][n]));
}
return 0;
}
UVA - 10891 Game of Sum(记忆化搜索 dp)
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原文地址:http://www.cnblogs.com/sola1994/p/4634620.html