Write a program to solve a Sudoku puzzle by filling the empty cells.
Empty cells are indicated by the character ‘.‘
.
You may assume that there will be only one unique solution.
A sudoku puzzle...
...and its solution numbers marked in red.
This is a simple problem on dfs method
public class Solution { public void solveSudoku(char[][] board){ List<Integer> blankCells = new ArrayList<Integer>(); //a sudoku board is a 9 by 9 array for(int i = 0; i < 81; ++i){ if(board[i / 9][ i % 9 ] == ‘.‘) blankCells.add(i); } dfs(board, 0, blankCells); } private boolean dfs(char[][] board, int start, List<Integer> blankCells) { if(start == blankCells.size()) return true; //dfs reaches the end //get the coordinates of the cell to be filled int currentCoordinate = blankCells.get(start); int row = currentCoordinate / 9; int column = currentCoordinate % 9; //fill a number in the cell for(int num = 1; num < 10; ++num) { //check the sudoku is valid after being filled num if(isValid(num, board,row,column)) { board[row][column] = (char)(num + ‘0‘); if(dfs(board,start + 1, blankCells)) return true; //if a solution can not be reached after the filling, we need to erase the filling for next try board[row][column] = ‘.‘; } } return false; } private boolean isValid(int num, char[][] board, int row, int column) { //check whether num is in the row, column and grid for(int i = 0; i < 9; ++i){ if(board[row][i] -‘0‘ == num) return false; //row if(board[i][column] - ‘0‘ == num) return false; //column if(board[3 *(row / 3) + i / 3][3 * (column / 3) + i % 3] - ‘0‘ == num) return false; } return true; } }
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原文地址:http://www.cnblogs.com/averillzheng/p/3825376.html