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骨牌无非两种放法,横着或竖着放,每次检查最r,c最小的没访问过的点即可。如果不能放就回溯。
最外面加一层认为已经访问过的位置,方便判断。
#include<bits/stdc++.h> const int MAXD = 56; const int MAXB = 29; const int MAXP = 7; bool used[MAXB];// used Bone int pip[MAXP][MAXP];// pip 2 Bone int tab[7][8]; int ans[8][9]; int cnt; void dfs(int r,int c) { while(ans[r][c]) { if(c == 8) { r++; c = -1; } c++; } if(r == 7) { for(int i = 0; i < 7; i++){ for(int j = 0; j < 8; j++){ printf("%4d",ans[i][j]); } putchar(‘\n‘); } putchar(‘\n‘); cnt++; return ; } int &p0 = tab[r][c]; if(!ans[r][c+1]){ // 横着放 int &p1 = tab[r][c+1]; int &bone = pip[p0][p1]; if(!used[bone]){ used[bone] = 1; ans[r][c+1] = ans[r][c] = bone; dfs(r,c+1); ans[r][c+1] = ans[r][c] = 0; used[bone] = 0; } } if(!ans[r+1][c]) { //竖着放 int &p2 = tab[r+1][c]; int &bone = pip[p0][p2]; if(!used[bone]){ used[bone] = 1; ans[r+1][c] = ans[r][c] = bone; dfs(r,c+1); ans[r+1][c] = ans[r][c] = 0; used[bone] = 0; } } } int main() { // freopen("in.txt","r",stdin); // freopen("my.txt","w",stdout); for(int h = 0,c = 0; h < 7; h++) for(int i = h; i < 7; i++){ pip[i][h] = pip[h][i] = ++c; } int *layout = *tab; int cas = 0; while(~scanf("%d",layout)){ if(cas) printf("\n\n\n"); memset(ans,0,sizeof(ans)); memset(used,0,sizeof(used)); cnt = 0; for(int i = 0; i < 7; i++) ans[i][8] = 233; for(int i = 0; i < 8; i++) ans[7][i] = 233; for(int i = 1; i < MAXD; i++) scanf("%d",layout+i); printf("Layout #%d:\n\n",++cas); for(int i = 0; i < 7; i ++){ for(int j = 0; j < 8; j++) printf("%4d",tab[i][j]); putchar(‘\n‘); } printf("\nMaps resulting from layout #%d are:\n\n",cas); dfs(0,0); printf("There are %d solution(s) for layout #%d.\n",cnt,cas); } return 0; }
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原文地址:http://www.cnblogs.com/jerryRey/p/4637051.html