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根据先序历遍和中序历遍输出后序历遍,并不需要真的建树,直接递归解决
#include<cstdio> #include<cstring> const int N = 30; char preOrder[N]; char midOrder[N]; char S[N]; int top; void solve(char *pre,char *mid,int len)//len>=1 { S[++top] = *pre; char *p = mid; while(*p != *pre) p++; p++; int tmp = p - mid; if(tmp < len) solve(pre + tmp, p ,len - tmp); if(tmp > 1) solve(pre + 1,mid,tmp - 1); return ; } int main() { int len; while(~scanf("%s",preOrder)){ scanf("%s",midOrder); top = 0; len = strlen(preOrder); solve(preOrder,midOrder,len); while(top) putchar(S[top--]); putchar(‘\n‘); } }
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原文地址:http://www.cnblogs.com/jerryRey/p/4637576.html