leetcode-58-Length of Last Word

标签：leetcode

Length of Last Word

Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example, 
Given s = "Hello World",
return 5.

返回最后一个单词的长度

class Solution {
public:
    int lengthOfLastWord(string s) {
        if(s.empty()) return 0;
        int n=s.length(),i,ans=0;
        n--;
        while(s[n]==' '&&n>=0)n--;
        for(i=n;i>=0;i--){
            if(s[i]!=' ') ans++;
            else break;
        }
        return ans;
    }
};

leetcode-58-Length of Last Word

标签：leetcode

原文地址：http://blog.csdn.net/u014705854/article/details/46836101