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Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 17028 Accepted Submission(s): 7319
#include<stdio.h> #include<string.h> #include<iostream> #include<algorithm> using namespace std; struct node{ int u,v,w,judge; }que[50000]; int n,cnt; bool cmp(struct node a,struct node b){ return a.w<b.w; } int father[500]; void init(){ for(int i=1;i<=n;i++) father[i]=i; } int find(int a){ if(father[a]!=a) father[a]=find(father[a]); return father[a];///不知道为什么return a;就是WA,按理说应该可以的啊,他俩不是相等的时候才返回嘛 } bool Union(int x1,int x2){ int t1=find(x1); int t2=find(x2); if(t1!=t2){ father[t1]=t2; return true; } return false; } int kruscal(){ int sum=0; int edge=0; sort(que,que+cnt,cmp); for(int i=0;i<cnt;i++){ if(Union(que[i].u,que[i].v)){ sum+=que[i].w; edge++; if(edge==n-1) return sum; } } } int main(){ while(scanf("%d",&n)!=EOF){ if(n==0) break; // memset(father,0,sizeof(father)); init(); cnt=n*(n-1)/2; for(int i=0;i<cnt;i++){ scanf("%d%d%d%d",&que[i].u,&que[i].v,&que[i].w,&que[i].judge); if(que[i].judge==1) que[i].w=0; } printf("%d\n",kruscal()); } return 0; }
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原文地址:http://www.cnblogs.com/13224ACMer/p/4638435.html