矩阵树定理求生成树计数模板.
原题是SPOJhighways
代码又长又丑…
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#define MAXN 20
#define eps 1e-9
using namespace std;
int A[MAXN][MAXN],D[MAXN][MAXN];//A是邻接矩阵D是度数矩阵
double C[MAXN][MAXN];//基尔霍夫矩阵
int T,n,m;
void in(int &x)
{
x = 0;
char ch = getchar();
while (!(ch >= ‘0‘ && ch <= ‘9‘)) ch = getchar();
while (ch >= ‘0‘ && ch <= ‘9‘) x = x * 10 + ch - ‘0‘,ch = getchar();
}
void gauss()
{
int now = 1;
for (int i = 1;i <= n;i++)
{
int x = now;
while (fabs(C[x][now]) < eps && x <= n) x++;
if (x == n + 1)
{
puts("0");
return;
}
for (int j = 1;j <= n;j++) swap(C[now][j],C[x][j]);
for (int j = now + 1;j <= n;j++)
{
double temp = C[j][now] / C[now][now];
for (int k = 1;k <= n;k++)
C[j][k] -= temp * C[now][k];
}
now++;
}
double ans=1;
for (int i = 1;i <= n;i++) ans*=C[i][i];
ans=fabs(ans);
printf("%.0lf\n",ans);
}
int main()
{
in(T);
while (T--)
{
memset(A,0,sizeof(A));
memset(D,0,sizeof(D));
in(n);in(m);
n--;
for (int i = 1;i <= m;i++)
{
int u,v;
in(u);in(v);
D[u][u]++;D[v][v]++;
A[u][v]++;A[v][u]++;
}
for (int i = 1;i <= n;i++)
for (int j = 1;j <= n;j++)
C[i][j] = D[i][j] - A[i][j];
gauss();
}
}
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原文地址:http://blog.csdn.net/creationaugust/article/details/46851013