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Given a non-negative number represented as an array of digits, plus one to the number.
The digits are stored such that the most significant digit is at the head of the list.
//不要再装逼使用unsigned int,这里使用UINT i，当i==0时进行i--，嘿，溢出了，循环继续
class Solution { public: vector<int> plusOne(vector<int>& digits) { vector<int> res; if(!digits.size()) return res; bool sign=true; int i,j,n=digits.size(); if(digits[n-1]!=9) //最后一位非9 { digits[n-1]+=1; return digits; } for(i=n-1;i>=0;i--) { if(sign) { if(digits[i]==9) { res.push_back(0); if(!i) res.push_back(1); //尽头补一位 }else { sign=false; res.push_back(digits[i]+1); for(j=i-1;j>=0;j--) { res.push_back(digits[j]); } } } } std::reverse(res.begin(),res.end()); return res; } };
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原文地址：http://www.cnblogs.com/jason1990/p/4641633.html
