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Given a matrix of m x n elements (m rows, n columns), return all elements of the matrix in spiral order.
For example,
Given the following matrix:
[ [ 1, 2, 3 ], [ 4, 5, 6 ], [ 7, 8, 9 ] ]
You should return [1,2,3,6,9,8,7,4,5]
.
public class Solution { //本题面试时考过,解决办法就是画图,注意边界 List<Integer> res; public List<Integer> spiralOrder(int[][] matrix) { res=new ArrayList<Integer>(); if(matrix==null||matrix.length==0) return res; int row=matrix.length; int col=matrix[0].length; int minRow=0; int minCol=0; int maxRow=row-1; int maxCol=col-1; while(maxRow>=minRow&&maxCol>=minCol){ print(matrix,minRow,maxRow,minCol,maxCol); minRow++; maxRow--; minCol++; maxCol--; } return res; } public void print(int[][] matrix,int minRow,int maxRow,int minCol,int maxCol){ if(minCol<=maxCol){ for(int i=minCol;i<=maxCol;i++){ res.add(matrix[minRow][i]); } } if(minRow<maxRow){ for(int i=minRow+1;i<=maxRow;i++){ res.add(matrix[i][maxCol]); } } if(minCol<maxCol&&minRow<maxRow){ for(int i=maxCol-1;i>=minCol;i--){ res.add(matrix[maxRow][i]); } } if(minCol<maxCol&&minRow<maxRow-1){ for(int i=maxRow-1;i>minRow;i--){ res.add(matrix[i][minCol]); } } } }
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原文地址:http://www.cnblogs.com/qiaomu/p/4641610.html