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HDU 2577 How to Type (线性dp)

时间:2015-07-13 00:51:48      阅读:147      评论:0      收藏:0      [点我收藏+]

标签:hdu   动态规划   线性dp   


How to Type

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)

Total Submission(s): 4616    Accepted Submission(s): 2084

Problem Description
Pirates have finished developing the typing software. He called Cathy to test his typing software. She is good at thinking. After testing for several days, she finds that if she types a string by some ways, she will type the key at least. But she has a bad habit that if the caps lock is on, she must turn off it, after she finishes typing. Now she wants to know the smallest times of typing the key to finish typing a string.
 
Input
The first line is an integer t (t<=100), which is the number of test case in the input file. For each test case, there is only one string which consists of lowercase letter and upper case letter. The length of the string is at most 100.
 
Output
For each test case, you must output the smallest times of typing the key to finish typing this string.
 
Sample Input
3 Pirates HDUacm HDUACM
 
Sample Output
8 8 8
Hint
The string “Pirates”, can type this way, Shift, p, i, r, a, t, e, s, the answer is 8. The string “HDUacm”, can type this way, Caps lock, h, d, u, Caps lock, a, c, m, the answer is 8 The string "HDUACM", can type this way Caps lock h, d, u, a, c, m, Caps lock, the answer is 8
 
Author
Dellenge
 
Source
HDU 2009-5 Programming Contest

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2577

题目大意:坑比题,给一些有大小写组成的字符串,问用键盘打出它们的最少按键次数
按键规则:对于每一个小写字母,加上shift可使其变成大写,注意shift不可以一直按着不放,还可以开大写锁Caps lock键,按完这键输入就变成大写,此时再按shift,则打出小写(mac的键盘貌似不是这样),注意每次大写锁,最后必须把它关上

题目分析:知道题以后就很简单了dp[i][0]和dp[i][1]分别表示到第i个字符大写锁关,开着时要按的最少次数,则有4种情况
如果到第i个字符为小写且此时开着大写锁,则它前一个必然是大写,因为如果前一个是小写,当前也是小写,我显然不需要开大写锁
dp[i][1] = dp[i - 1][1] + 2
如果到第i个字符为小写且此时没开大写锁,直接打就行了
dp[i][0] = dp[i - 1][0] + 1
如果到第i个字符为大写且此时开着大写锁,则为前一个开着大写锁的情况加1和前一个没开大写锁的情况加2的最小值,表示开锁
dp[i][1] = min(dp[i - 1][1] + 1, dp[i - 1][0] + 2)
如果到第i个字符为大写且此时没开大写锁,则为前一个没开大写锁的情况加2(按shift)和前一个开着大写锁的情况加2的最小值,表示关锁
dp[i][0] = min(dp[i - 1][0] + 2, dp[i - 1][1] + 2)

#include <cstdio>
#include <cstring>
#include <algorithm>
using namespace std;
int const MAX = 105;
char s[MAX];
int dp[MAX][2];

bool judge(char ch)
{
    if(ch >= 'A' && ch <= 'Z')
        return true;
    return false;
}

int main()
{
    int T;
    scanf("%d", &T);
    while(T--)
    {
        scanf("%s", s + 1);
        int len = strlen(s + 1);
        memset(dp,0, sizeof(dp));
        dp[0][1] =  1;
        for(int i = 1; i <= len; i++)
        {
            if(judge(s[i]))
            {
                dp[i][1] = min(dp[i - 1][1] + 1, dp[i - 1][0] + 2);
                dp[i][0] = min(dp[i - 1][0] + 2, dp[i - 1][1] + 2);
            }
            else
            {
                dp[i][1] = dp[i - 1][1] + 2;
                dp[i][0] = dp[i - 1][0] + 1;
            }
        }
        printf("%d\n", min(dp[len][0], dp[len][1] + 1));
    }
}



版权声明:本文为博主原创文章,未经博主允许不得转载。

HDU 2577 How to Type (线性dp)

标签:hdu   动态规划   线性dp   

原文地址:http://blog.csdn.net/tc_to_top/article/details/46854871

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