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Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World",
return 5.
public class Solution { public int lengthOfLastWord(String s) { int res=0; int flag=0; //解题思路：flag代表后面是否出现过非空格的字符，当flag=1代表后面出现非空格，并且该字符为空格时，遍历结束 /* for(int i=s.length()-1;i>=0;i--){ if(s.charAt(i)!=‘ ‘){ res++; flag=1; }else if(flag==1&&s.charAt(i)==‘ ‘) break; } return res;*/ //////////////第二种方式，先排除最后一位是空格的情况，本题题意“a ”应该返回1 int i=s.length()-1; while(i>=0){ if(s.charAt(i)!=‘ ‘) break; i--; } for(;i>=0;i--){ if(s.charAt(i)==‘ ‘) return res; else if(s.charAt(i)!=‘ ‘){ res++; } } return res; } }
[leedcode 58] Length of Last Word
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原文地址：http://www.cnblogs.com/qiaomu/p/4642262.html
