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Problem Description
4 6 11 0 7 5 13 9 78 4 81 6 22 4 1 40 9 34 16 10 11 22 0 33 39 6
242
#include <cstdio> #include <cstring> #include <algorithm> using namespace std; int const MAX = 2 * 1e5 + 5; int row[MAX], a[MAX], dp[MAX], tmp[MAX]; int main() { int n, m; while(scanf("%d %d", &n, &m) != EOF) { memset(tmp, 0, sizeof(tmp)); memset(dp, 0, sizeof(dp)); for(int i = 1; i <= m * n; i++) scanf("%d", &a[i]); int cnt = 1; for(int i = 1; i <= m * n; i += m) { for(int j = 2; j <= m; j++) { tmp[1] = a[i]; tmp[j] = max(tmp[j - 1], a[i + j - 1] + tmp[j - 2]); } row[cnt ++] = tmp[m]; } dp[1] = row[1]; for(int i = 2; i < cnt; i++) dp[i] = max(dp[i - 1], dp[i - 2] + row[i]); printf("%d\n", dp[cnt - 1]); } }
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原文地址:http://blog.csdn.net/tc_to_top/article/details/46869323