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题目:
Invert a binary tree.
4 / 2 7 / \ / 1 3 6 9to
4 / 7 2 / \ / 9 6 3 1Trivia:
Google: 90% of our engineers use the software you wrote (Homebrew), but you can’t invert a binary tree on a whiteboard so fuck off.
代码:
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: TreeNode* invertTree(TreeNode* root) { if ( !root ) return root; TreeNode* tmp = root->left; root->left = Solution::invertTree(root->right); root->right = Solution::invertTree(tmp); return root; } };
tips:
翻转二叉树跟交换两个int差不多。。。重点是留一个tmp。
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原文地址:http://www.cnblogs.com/xbf9xbf/p/4645147.html