Description
Input
Output
Sample Input
3 565 9876543210 9876105432
Sample Output
556 1234567890 1678905432
思路:贪心的从后向前开始,大的放后面,然后找到当前最小的,从后面来也可以排除0放到第一个的可能
#include <iostream> #include <cstdio> #include <cstring> #include <algorithm> using namespace std; const int MAXN = 200; char str[MAXN]; char head[MAXN],tail[MAXN]; int main() { int t; scanf("%d", &t); while (t--) { scanf("%s", str); int n = strlen(str); int a = 0, b = 0; int cnt = n-1; while (str[cnt] == '0' && cnt > 0) cnt--; for (int i = cnt; i >= 0; i--) if (str[cnt] > str[i] && str[i] != '0') cnt = i; head[a++] = str[cnt]; for (int i = n-1; i > cnt; i--) tail[b++] = str[i]; while (a+b < n && cnt > 0) { int tmp = cnt-1; for (int j = tmp-1; j >= 0; j--) if (str[j] < str[tmp]) tmp = j; head[a++] = str[tmp]; for (int j = cnt-1; j > tmp; j--) tail[b++] = str[j]; cnt = tmp; } for (int i = 0; i < a; i++) printf("%c", head[i]); for (int j = b-1; j >= 0; j--) printf("%c", tail[j]); printf("\n"); } return 0; }
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原文地址:http://blog.csdn.net/u011345136/article/details/36899929