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【LeetCode】237. Delete Node in a Linked List

时间:2015-07-15 16:24:29      阅读:117      评论:0      收藏:0      [点我收藏+]

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Delete Node in a Linked List

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4 after calling your function.

 

后一个赋值给前一个,注意结尾的置空与删除。

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */
class Solution {
public:
    void deleteNode(ListNode* node) {
        ListNode* cur = node;
        ListNode* post = cur->next; // except the tail, thus has access to the next
        while(true)
        {
            cur->val = post->val;
            if(post->next == NULL)
            {
                cur->next = NULL;
                return;
            }
            else
            {
                cur = post;
                post = post->next;
            }
        }
    }
};

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【LeetCode】237. Delete Node in a Linked List

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原文地址:http://www.cnblogs.com/ganganloveu/p/4648589.html

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