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BNUOJ 5227 Max Sum

时间:2014-07-08 23:42:52      阅读:273      评论:0      收藏:0      [点我收藏+]

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Max Sum

1000ms
32768KB
 
This problem will be judged on HDU. Original ID: 1003
64-bit integer IO format: %I64d      Java class name: Main
 
Given a sequence a[1],a[2],a[3]......a[n], your job is to calculate the max sum of a sub-sequence. For example, given (6,-1,5,4,-7), the max sum in this sequence is 6 + (-1) + 5 + 4 = 14.

Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line starts with a number N(1<=N<=100000), then N integers followed(all the integers are between -1000 and 1000).
 

Output

For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line contains three integers, the Max Sum in the sequence, the start position of the sub-sequence, the end position of the sub-sequence. If there are more than one result, output the first one. Output a blank line between two cases.
 

Sample Input

2
5 6 -1 5 4 -7
7 0 6 -1 1 -6 7 -5
 

Sample Output

Case 1:
14 1 4

Case 2:
7 1 6


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 1 #include <iostream>
 2 #include <cstdio>
 3 #include <cstring>
 4 #include <cstdlib>
 5 #include <vector>
 6 #include <climits>
 7 #include <algorithm>
 8 #include <cmath>
 9 #define LL long long
10 using namespace std;
11 int dp[100010],num[100010];
12 int main(){
13     int kase,i,index,ans,n,k = 1;
14     scanf("%d",&kase);
15     while(kase--){
16         scanf("%d",&n);
17         for(i = 1; i <= n; i++)
18             scanf("%d",dp+i);
19         num[1] = 0;
20         ans = dp[index = 1];
21         for(i = 2; i <= n; i++){
22             if(dp[i] <= dp[i-1]+dp[i]){
23                 dp[i] = dp[i-1]+dp[i];
24                 num[i] = num[i-1]+1;
25             }else num[i] = 0;
26             if(ans < dp[i]) ans = dp[index = i];
27         }
28         printf("Case %d:\n",k++);
29         printf("%d %d %d\n",ans,index-num[index],index);
30         if(kase) putchar(\n);
31     }
32     return 0;
33 }
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BNUOJ 5227 Max Sum,布布扣,bubuko.com

BNUOJ 5227 Max Sum

标签:style   blog   http   java   color   strong   

原文地址:http://www.cnblogs.com/crackpotisback/p/3830305.html

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