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zoj 2432 模板LCIS

时间:2015-07-17 22:14:21      阅读:90      评论:0      收藏:0      [点我收藏+]

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输出一条 LCIS

 1 #include "bits/stdc++.h"
 2 using namespace std;
 3 int T;
 4 int len1, len2;
 5 int s1[510], s2[510];
 6 int dp[510][510];
 7 int choice[510][510];
 8 
 9 
10 int main()
11 {
12     scanf("%d", &T);
13     while(T--) {
14         memset(dp, 0, sizeof(dp));
15         memset(choice, 0, sizeof(choice));
16         scanf("%d", &len1);
17         int i, j;
18         for(i = 1; i <= len1; ++i) {
19             scanf("%d", &s1[i]);
20         }
21         scanf("%d", &len2);
22         for(j = 1; j <= len2; ++j) {
23             scanf("%d", &s2[j]);
24         }
25 
26         for(i = 1; i <= len1; ++i) {
27             int k = 0;
28             for(j = 1; j <= len2; ++j) {
29                 if(s1[i] == s2[j]) {
30                     dp[i][j] = dp[i - 1][k] + 1;
31                     choice[i][j] = 1000 * (i - 1) + k;
32                 }
33                 else {
34                     dp[i][j] = dp[i - 1][j];
35                     choice[i][j] = choice[i - 1][j];
36                     if(s1[i] > s2[j] && dp[i - 1][k] < dp[i - 1][j]) {
37                         k = j;
38                     }
39                 }
40 //                printf("dp[%d][%d] == %d\n", i ,j, dp[i][j]);
41             }
42         }
43 
44         int end_pos;
45         int res = 0;
46         for(j = 1; j <= len2; ++j) {
47             if(res < dp[len1][j]) {
48                 res = dp[len1][j];
49                 end_pos = j;
50             }
51         }
52         printf("%d\n", res);
53         if(res == 0) {
54             continue;
55         }
56         int state_1, state_2, tmp;
57         state_1 = len1;
58         state_2 = end_pos;
59         int tot_ans = 0;
60         while(state_2) {
61             ++tot_ans;
62             s1[tot_ans] = s2[state_2];
63             tmp = choice[state_1][state_2];
64             state_1 = tmp / 1000;
65             state_2 = tmp % 1000;
66         }
67         while(tot_ans) {
68             printf("%d ", s1[tot_ans]);
69             --tot_ans;
70         }
71         printf("\n");
72     }
73 }
74 //2
75 //5
76 //1 4 2 5 -12
77 //4
78 //-12 1 2 4
79 
80 
81 //2
82 //5
83 //1 2 3 4 5
84 //1
85 //9

 

zoj 2432 模板LCIS

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原文地址:http://www.cnblogs.com/AC-Phoenix/p/4655615.html

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