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Time Limit: 3000MS | Memory Limit: 131072K | |
Total Submissions: 11859 | Accepted: 3742 |
Description
The galaxy war between the Empire Draco and the Commonwealth of Zibu broke out 3 years ago. Draco established a line of defense called Grot. Grot is a straight line with N defense stations. Because of the cooperation of the stations, Zibu’s Marine Glory cannot march any further but stay outside the line.
A mystery Information Group X benefits form selling information to both sides of the war. Today you the administrator of Zibu’s Intelligence Department got a piece of information about Grot’s defense stations’ arrangement from Information Group X. Your task is to determine whether the information is reliable.
The information consists of M tips. Each tip is either precise or vague.
Precise tip is in the form of P A B X
, means defense station A is X light-years north of defense station B.
Vague tip is in the form of V A B
, means defense station A is in the north of defense station B, at least 1 light-year, but the precise distance is unknown.
Input
There are several test cases in the input. Each test case starts with two integers N (0 < N ≤ 1000) and M (1 ≤ M ≤ 100000).The next M line each describe a tip, either in precise form or vague form.
Output
Output one line for each test case in the input. Output “Reliable” if It is possible to arrange N defense stations satisfying all the M tips, otherwise output “Unreliable”.
Sample Input
3 4 P 1 2 1 P 2 3 1 V 1 3 P 1 3 1 5 5 V 1 2 V 2 3 V 3 4 V 4 5 V 3 5
Sample Output
Unreliable Reliable
Source
POJ Monthly--2006.08.27, Dagger
http://blog.csdn.net/lyy289065406/article/details/6648688
ac代码
#include<stdio.h> #include<string.h> #include<queue> #include<string> #include<iostream> #define INF 0xfffffff using namespace std; int head[1010],vis[1010],cnt,dis[1010],s,cot[1010]; int n,m; struct s { int u,v,w,next; }edge[300200]; void add(int u,int v,int w) { edge[cnt].u=u; edge[cnt].v=v; edge[cnt].w=w; edge[cnt].next=head[u]; head[u]=cnt++; } int spfa(int s) { int i; for(i=1;i<=n;i++) { dis[i]=INF; } memset(vis,0,sizeof(vis)); memset(cot,0,sizeof(cot)); dis[s]=0; vis[s]=1; queue<int>q; q.push(s); while(!q.empty()) { int u=q.front(); q.pop(); vis[u]=0; cot[u]++; if(cot[u]>n) return 0; for(i=head[u];i!=-1;i=edge[i].next) { int v=edge[i].v; int w=edge[i].w; if(dis[v]>dis[u]+w) { dis[v]=dis[u]+w; if(!vis[v]) { vis[v]=1; q.push(v); } } } } return 1; } int main() { // int n,m; while(scanf("%d%d",&n,&m)!=EOF) { char str[2]; int i; memset(head,-1,sizeof(head)); cnt=0; for(i=0;i<m;i++) { scanf("%s",str); if(str[0]=='P') { int a,b,c; scanf("%d%d%d",&a,&b,&c); add(a,b,c); add(b,a,-c); } else { int a,b; scanf("%d%d",&a,&b); add(b,a,-1); } } s=n+1; for(i=1;i<=n;i++) { add(s,i,0); } if(spfa(s)) printf("Reliable\n"); else printf("Unreliable\n"); } }
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POJ 题目2983 Is the Information Reliable?(差分约束)
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原文地址:http://blog.csdn.net/yu_ch_sh/article/details/46931167