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LeetCode#191 Number of 1 Bits

时间:2015-07-18 15:29:39      阅读:108      评论:0      收藏:0      [点我收藏+]

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Problem Definition:

Write a function that takes an unsigned integer and returns the number of ’1‘ bits it has (also known as the Hamming weight).

For example, the 32-bit integer ’11‘ has binary representation 00000000000000000000000000001011, so the function should return 3.

Solution:

  基本方法,Python实现,直观到不好意思。

1 def hammingWeight(n):
2     count=0
3     count+=(n%2)
4     b=n/2
5     while b!=0:
6         count+=(b%2)
7         b=b/2
8     return count

  但是上面的代码不够“Python”,应该这么的:(reference1)(reference2)

def hammingWeight(n):
    return (bin(n)[2:]).count(1)

 

  如果是C/C++实现,用位操作比较方便

LeetCode#191 Number of 1 Bits

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原文地址:http://www.cnblogs.com/acetseng/p/4656811.html

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