标签：codeforces 水题 枚举
转载请注明出处：http://blog.csdn.net/u012860063/article/details/37509207
题目链接：http://codeforces.com/contest/445/problem/C
DZY Loves Physics
DZY loves Physics, and he enjoys calculating density.
Almost everything has density, even a graph. We define the density of a non-directed graph (nodes and edges of the graph have some values) as follows:
Once DZY got a graph G, now he wants to find a connected induced subgraph G‘ of the graph, such that the density of G‘ is as large as possible.
An induced subgraph G‘(V‘,?E‘) of a graph G(V,?E) is a graph that satisfies:
;
if
and only if 
,
and edge 
;Help DZY to find the induced subgraph with maximum density. Note that the induced subgraph you choose must be connected.
The first line contains two space-separated integers n (1?≤?n?≤?500), 
.
Integer n represents the number of nodes of the graph G, m represents
the number of edges.
The second line contains n space-separated integers xi (1?≤?xi?≤?106), where xi represents the value of the i-th node. Consider the graph nodes are numbered from 1 to n.
Each of the next m lines contains three space-separated integers ai,?bi,?ci (1?≤?ai?<?bi?≤?n; 1?≤?ci?≤?103), denoting an edge between node ai and bi with value ci. The graph won‘t contain multiple edges.
Output a real number denoting the answer, with an absolute or relative error of at most 10?-?9.
1 0 1
0.000000000000000
2 1 1 2 1 2 1
3.000000000000000
5 6 13 56 73 98 17 1 2 56 1 3 29 1 4 42 2 3 95 2 4 88 3 4 63
2.965517241379311
In the first sample, you can only choose an empty subgraph, or the subgraph containing only node 1.
In the second sample, choosing the whole graph is optimal.
题意： 给出一个源图， 要求寻找一个密度（点的值/边的值）最大的子图；
当然子图有三个要满足的要求！
思路：枚举每天边，及其端点的值。为什么这就是最大密度的子图呢？
因为子图必然是由很多边和端点所组成的，而想要最大密度的子图，必然子图中其中的一条边的密度是最大的（至少不会小于子图的总密度），这样只需要找出密度最大的边就是答案！（纯属绰见）；
好吧，昨晚我承认自己煞笔了， 没有做出来这道大水题！
代码如下：
#include <cstdio>
#define N 517
double MAX(double a, double b)
{
return a>b?a:b;
}
int main()
{
int n, m;
int x[N];
int a, b, c;
while(~scanf("%d%d",&n,&m))
{
int i, j;
for(i = 1; i <= n; i++)
{
scanf("%d",&x[i]);
}
double max = 0, t;
for(i = 1; i <= m; i++)
{
scanf("%d%d%d",&a,&b,&c);
t =(double) (x[a]+x[b])/c;
max = MAX(max, t);
}
printf("%.15f\n",max);
}
return 0;
}
CodeForces 444C. DZY Loves Physics（枚举+水题）,布布扣,bubuko.com
CodeForces 444C. DZY Loves Physics（枚举+水题）
标签：codeforces 水题 枚举
原文地址：http://blog.csdn.net/u012860063/article/details/37509207
