Method 1: Add one list into the other list.
For example, if list1is {22, 33, 44, 55} and list2 is {66, 77, 88, 99},then append(list1, list2)will change list1to {22, 33, 44, 55, 44, 66, 77, 88, 99}.
static void append(Node list1, Node list2) { if (list1 == null) { throw new IllegalArgumentException(); } while (list1.next != null) { list1 = list1.next; } list1.next = list2; }
The output is as follows:
Method2: Gets a new list combined by two list
For example, if list1 is {22, 33, 44, 55} and list2 is {66, 77, 88, 99}, then concat(list1, list2)will return the new list {22, 33, 44, 55, 44, 55, 66, 77, 88}.
Note that the three lists should be completely independent of each other. Changing one list should have no effect upon the others.
static Node concat(Node list1, Node list2) { Node list3 = new Node(0); Node p = list1; Node q = list3; while(p != null) { q.next = new Node(p.data); p = p.next; q = q.next; } p = list2; while(p != null) { q.next = new Node(p.data); q = q.next; p = p.next; } return list3.next; }
The output is as follows:
Method 3 : Replace the value of element number i with x
void set(Node list, int i, int x)
For example, if list is {22, 33, 44, 55, 66, 77, 88, 99}, then set(list, 2, 50) will change List to {22, 33, 50, 55, 66, 44, 88, 99}
Solution 1: static void set(Node list, int i, int x) { Node p = list; int count = 0; while (p != null) { if (count == i) { p.data = x; break; } p = p.next; count++; } } Solution2: static void set(Node list, int i, int x) { if (i < 0) { throw new IllegalArgumentException(); } for (int j = 0; j < i; j++) { if (list == null) { throw new IllegalStateException(); } list = list.next; } list.data = x; }
The output is as follows:
【DataStructure】Some useful methods about linkedList(二),布布扣,bubuko.com
【DataStructure】Some useful methods about linkedList(二)
原文地址:http://blog.csdn.net/sxb0841901116/article/details/37399773